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Question: What is the 20th number in the sequence \(1,4,9,16,25,36\)?...

What is the 20th number in the sequence 1,4,9,16,25,361,4,9,16,25,36?

Explanation

Solution

To find the missing term in a sequence, find the logic behind the sequence. In the given sequence 1,4,9,16,25,361,4,9,16,25,36, observe that all the terms are squares. So, here the pattern would be xn=n2{x_n} = {n^2}, where xn{x_n} is the number of terms to be found and n2{n^2} is the term we have to find. So, the 20th term would be x20{x_{20}}.

Complete step by step solution:
In this question, we are given a sequence 1,4,9,16,25,361,4,9,16,25,36 and we have to find what will be the 20th term of this sequence.
First of all, what is a sequence?
A sequence is a set of numbers that are ordered.
For example: 2,4,6,8...2,4,6,8...
This is a sequence of even numbers and the next term will be 10.
Each number in the sequence is called a term.
Now, to find a missing term in the sequence, first find a pattern behind the series.
Like in the above example, we were given a sequence of even numbers, so we could figure out the next term based on that pattern.
But, in our question, we are given a sequence of squares.
1,4,9,16,25,36=12,22,32,42,52,62\Rightarrow 1,4,9,16,25,36 = {1^2},{2^2},{3^2},{4^2},{5^2},{6^2}
Observe that here, the pattern is xn=n2{x_n} = {n^2}.
Where xn{x_n} is the number of the term and n2{n^2} is the term.
So, if we want to find the 1st term, put n=1n = 1.
x1=(1)2=1\Rightarrow {x_1} = {\left( 1 \right)^2} = 1
But, we have to find the 20th term. So, put n=20n = 20.
x20=(20)2=400\Rightarrow {x_{20}} = {\left( {20} \right)^2} = 400
Therefore, the 20th term in the sequence 1,4,9,16,25,361,4,9,16,25,36 will be 400400.

Note:
This is a logic based question and there can be multiple patterns behind this sequence. So, there may be more than one correct answer to this question. For example: Another pattern for this sequence is that the difference between two consecutive terms is an odd number.