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Question: What is \[\tan (\dfrac{\theta }{2})\] in terms of trigonometric functions of a unit \(\theta \)?...

What is tan(θ2)\tan (\dfrac{\theta }{2}) in terms of trigonometric functions of a unit θ\theta ?

Explanation

Solution

Trigonometry is a branch of mathematics that studies the relationship between the angles and the sides of a right-angled triangle. The relationship between sides and angles is established for six trigonometric functions.

Complete step by step solution:
A branch of mathematics that studies the relationship between the angles and the sides of a right-angled triangle. There are six trigonometric functions. Every trigonometric function can be represented in terms of the other trigonometric functions.
In trigonometry, the tangent function is a periodic function that is very useful. The trigonometric ratio between the adjacent side and the opposite side of a right triangle comprising that angle is called the tangent of an angle.
The identity tanθ=2tan(θ2)1tan2(θ2)\tan \theta = \dfrac{{2\tan (\dfrac{\theta }{2})}}{{1 - {{\tan }^2}(\dfrac{\theta }{2})}},
Let us take tan(θ2)=x\tan (\dfrac{\theta }{2}) = x, then the above equation will become:
tanθ=2x1x2\tan \theta = \dfrac{{2x}}{{1 - {x^2}}}
tanθ×(1x2)=2x\Rightarrow tan\theta \times (1 - {x^2}) = 2x
tanθx22x+tanθ=0\Rightarrow - \tan \theta {x^2} - 2x + \tan \theta = 0
tanθx2+2xtanθ=0\Rightarrow \tan \theta {x^2} + 2x - \tan \theta = 0
Using the Quadratic formula, we get:
x=2±224×tanθ×(tanθ)2tanθx = \dfrac{{ - 2 \pm \sqrt {{2^2} - 4 \times \tan \theta \times ( - \tan \theta )} }}{{2\tan \theta }}
x=2±4+4×tan2θ2tanθ\Rightarrow x = \dfrac{{ - 2 \pm \sqrt {4 + 4 \times {{\tan }^2}\theta } }}{{2\tan \theta }}
x=2±2sec2θ2tanθ\Rightarrow x = \dfrac{{ - 2 \pm 2\sqrt {{{\sec }^2}\theta } }}{{2\tan \theta }}
x=2±2secθ2tanθ\Rightarrow x = \dfrac{{ - 2 \pm 2\sec \theta }}{{2\tan \theta }}
x=1±secθtanθ\Rightarrow x = \dfrac{{ - 1 \pm \sec \theta }}{{\tan \theta }}
Substituting tan(θ2)=x\tan (\dfrac{\theta }{2}) = x into the above equation, we get:
tan(θ2)=1±secθtanθ\Rightarrow \tan (\dfrac{\theta }{2}) = \dfrac{{ - 1 \pm \sec \theta }}{{\tan \theta }}
Thus, tan(θ2)\tan (\dfrac{\theta }{2}) in terms of trigonometric functions of a unit θ\theta is 1±secθtanθ\dfrac{{ - 1 \pm \sec \theta }}{{\tan \theta }}.

Additional Information:
There are many uses for trigonometric functions in our real lives. It is used in oceanography to figure out how high the waves are in the seas. The sine and cosine functions are important in the study of periodic functions, which include sound and light waves. Trigonometry and Algebra make up Calculus.

Note:
The trigonometric functions sine and cosine are used to create each of the trigonometric functions in some way. The tangent of xx is said to be the sine of xx divided by the cosine of xx.