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Question

Physics Question on Atoms

What is size of gold nuclei?

A

3R03R_0

B

4R04R_0

C

5R05R_0

D

5.8R05.8R_0

Answer

5.8R05.8R_0

Explanation

Solution

Nuclear radius of gold (79Au198)(_{79}Au^{198})
RAu=R0(A1/3)R_{Au}=R_0(A^{1/3})
=(198)1/3R0=(198)^{1/3}R_0
=5.8×R0=5.8 \times R_0
(where R0=1.2×1015m=1.2fm)R_0=1.2 \times 10^{-15}m=1.2 fm)