Question

What is ratio of Bohr magneton to the nuclear magneton?

• A. $m_p/m_e$
• B. $m^2_p/m^2_e$
• C. $1$
• D. $\frac{m_{e}}{m_{p}}$

Answer 1

Answer: (A)

$m_p/m_e$

Answer 2

Magnetic moment associated with electrons orbitting around the nucleus is given in terms of Bohr magneton $\left(\mu_{B}\right)$ $\mu_{B} = \frac{eh}{2m_{e}}$ e = electronic charge, me = electronic mass. In nuclear physics, magnetic moments associated with the spins of protons and neutrons are expressed in nuclear magnetons $\left(\mu_{N}\right)$ $\mu_{N} = \frac{eh}{2m_{p}}$ $m_{p}$ = mass of a proton. $\Rightarrow\, \frac{\mu_{B}}{\mu_{N}} = \frac{m_{p}}{m_{e}}$