Solveeit Logo

Question

Question: What is R in the mathematical expression of the ideal gas law?...

What is R in the mathematical expression of the ideal gas law?

Explanation

Solution

Hint : The gas laws comprise of the five primary laws namely (i) Charles' Law, (ii) Boyle's Law, (iii) Avogadro's Law, (iv) Gay-Lussac Law and (v) Combined Gas Law. These five gas laws invented the relationship between temperature, pressure, volume and the amount of gas.

Complete Step By Step Answer:
The ideal gas equation refers to the equation of a state of hypothetical ideal gas. In the question, we have been asked about ‘R’ in ideal gas law expression. So first of all, let us see the expression of ideal gas law:
PV=nRTPV = nRT where PP is pressure, VV is volume, nn is amount of substance, RR is ideal gas constant and TT is temperature.
Let us now discuss the unit for each of these terms used in ideal gas equation one by one:
PP - The most common units to express pressure include atm, mm Hg, torr, Pa, kPa, baratm,{\text{ }}mm{\text{ }}Hg,{\text{ }}torr,{\text{ }}Pa,{\text{ }}kPa,{\text{ }}bar
VV - The most common units to express volume include L, m3, cm3, dm3L,{\text{ }}{m^3},{\text{ }}c{m^3},{\text{ }}d{m^3}
nn - It is actually the number of moles, thus units are molmol
TT - The most common units to express temperature include oC, K,oF  ^oC,{\text{ }}K{,^o}F\;
RR - The ideal gas constant can be actually expressed in multiple units, depending upon what it has been used for PP , VV and TT . The possible values as well as units of RR are listed below. RR can be expressed as follows:
R=PVnTR = \dfrac{{PV}}{{nT}}
The most widely employed expression for RR is when VV is given in litres ( LL ), PP is given in atmosphere ( atmatm ), and TT is given in Kelvin ( KK ) so RR can be expressed as:
R=0.0821L.atmmol.KR = 0.0821\dfrac{{L.atm}}{{mol.K}}
The other widely employed expression for RR is when VV is given in litres ( m3{m^3} ), PP is given in atmosphere ( PaPa ) which results into Joules ( JJ ) when multiplied and TT is given in Kelvin ( KK ) so RR can be expressed as:
R=8.314Jmol.KR = 8.314\dfrac{J}{{mol.K}}

Note :
You must always make sure regarding the units being employed for RR that must match the units of PP , VV , nn and TT . Keep in mind that real gases are non-ideal which do not follow the ideal gas law exactly. For real gases, two changes have been incorporated like (i) a constant has been added to the pressure (P) and (ii) a different constant has been subtracted from the volume (V). Thus, the new equation for real gas law is: (P+an2)×(Vnb)=nRT(P + a{n^2}) \times (V - nb) = nRT .