Question

What is pOH of an aqueous solution with hydrogen ion concentration equal to $800^{o}C$?

• A. $K_{P}$
• B. $N_{2(g)} + O_{2(g)}2NO_{(g)}$
• C. $800^{o}C$
• D. $K_{c}$

Answer 1

Answer: (A)

$K_{P}$

Answer 2

: $pH = - \log\lbrack H^{+}\rbrack = - \log(3 \times 10^{- 5}) = 4.5229$

pOH = 14 – pH, 14 - $4.5229 = 9.47$