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Question: What is molar conductivity? How is it related to the concentration of electrolyte?...

What is molar conductivity? How is it related to the concentration of electrolyte?

Explanation

Solution

Molar conductance gives the conductance of a solution containing a definite amount of the electrolyte. This definite amount is in terms of moles. With increase in dilution, the molar conductivity increases.

Complete answer:
If you measure the conductance of one mole of a solution, you will obtain molar conductivity.
Write the expression for the molar conductance of an electrolyte solution as shown below:
Λm=1000×κC{\Lambda _m} = \dfrac{{1000 \times \kappa }}{C}
Here, Λm{\Lambda _m} represents the molar conductance of an electrolyte solution, κ\kappa represents the specific conductance of that electrolyte solution and C represents the concentration of electrolyte.
The specific conductance is the conductance of unit volume of electrolyte solution placed between two platinum electrodes having unit cross section area.
The unit of the specific conductance κ\kappa is S/cm{\text{S/cm}} or siemens per centimeter. The unit of concentration is moles per litre or mol/dm3{\text{mol/d}}{{\text{m}}^3} .
Substitute units in equation (1) and find out the unit of the molar conductance.

Λm=1000cm3dm3×S/cmmol/dm3 Λm=S cm2mol1  {\Lambda _m} = \dfrac{{1000{\text{c}}{{\text{m}}^3}{\text{d}}{{\text{m}}^{ - 3}} \times {\text{S/cm}}}}{{{\text{mol/d}}{{\text{m}}^3}}} \\\ {\Lambda _m} = {\text{S c}}{{\text{m}}^2}{\text{mo}}{{\text{l}}^{ - 1}} \\\

From the expression Λm=1000×κC{\Lambda _m} = \dfrac{{1000 \times \kappa }}{C} you can say that the molar conductivity is inversely proportional to the concentration. With increase in the concentration, the molar conductivity decreases. Molar conductivity is directly proportional to dilution. With increase in dilution, the molar conductivity increases.

Note:
The unit siemens is also known as mho or ohm1{\text{oh}}{{\text{m}}^{ - 1}}.
Hence, you can also write the units of molar conductance as either mho cm2mol1{\text{mho c}}{{\text{m}}^2}{\text{mo}}{{\text{l}}^{ - 1}} or ohm1cm2mol1{\text{oh}}{{\text{m}}^{ - 1}}{\text{c}}{{\text{m}}^2}{\text{mo}}{{\text{l}}^{ - 1}} .