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Question: What is meant by power of a lens? Write its SI unit. A student uses a lens of focal length of 40 cm ...

What is meant by power of a lens? Write its SI unit. A student uses a lens of focal length of 40 cm and another of -20 cm. Write the nature and power of the lens.

Explanation

Solution

Define a lens. A lens will either converge or diverge the incoming light rays from each-other or from the principal axis. We can measure this amount of convergence or divergence of a lens. This gives the strength or power of a lens. Obtain the mathematical expression giving the total power of a lens system.

Complete step-by-step answer:
Power of a lens can be defined as the bending strength of a lens. The more the lens can bend the light rays passing through it, the more the power of the lens.
The power of a lens can be defined as the reciprocal of the focal length of the lens. Mathematically we can express this as,
P=1fP=\dfrac{1}{f}
Where, P is the power of the lens and f is the focal length of the lens in meters.
The unit of focal length is dioptres(D).
If we have two thin lens of power P1{{P}_{1}} and P2{{P}_{2}} close together, the total power of the lens system is given as,
P=P1+P2P={{P}_{1}}+{{P}_{2}}
Now, we have two lenses with focal length f1=40cm=0.4m{{f}_{1}}=40cm=0.4m and f2=20cm=0.2m{{f}_{2}}=-20cm=-0.2m
Total power of the lens system will be,
P=P1+P2 P=1f1+1f2 P=10.4+1(0.2) P=10.410.2 P=2.55 P=2.5D \begin{aligned} & P={{P}_{1}}+{{P}_{2}} \\\ & P=\dfrac{1}{{{f}_{1}}}+\dfrac{1}{{{f}_{2}}} \\\ & P=\dfrac{1}{0.4}+\dfrac{1}{\left( -0.2 \right)} \\\ & P=\dfrac{1}{0.4}-\dfrac{1}{0.2} \\\ & P=2.5-5 \\\ & P=-2.5D \\\ \end{aligned}
So, the power of the lens is -2.5D.
Since the power is negative, the light will diverge from each other. So, we can say that the system of the lenses acts like a convex lens.

Note: A convex lens has a positive focal length. So, the power of a convex lens is positive. Again, the focal length of a concave lens is negative. So, the power of a concave lens is negative. So, we can say that if a lens diverges the light rays, it will have negative power and if a lens converges the light rays, it will have positive power.