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Question: What is Leibniz Notation?...

What is Leibniz Notation?

Explanation

Solution

For solving this question you should know about the Leibniz notation. According to Leibniz notation we use the symbols dxdx and dydy to represent the infinitely small increments of xx and yy. As the Δx\Delta x and Δy\Delta y represent the finite increments of xx and yy respectively. We can write the first and second derivative as dydx\dfrac{dy}{dx} and d2ydx2\dfrac{{{d}^{2}}y}{d{{x}^{2}}} with respect to xx in Leibniz notation.

Complete step by step solution:
According to the question we have to explain the Leibniz notation. The Leibniz notation is used to represent the infinitely small increments of xx and yy. If we look up an example for it then it will be clear exactly.
Example: What is the derivative of yy with respect to xx, given that: 4y2+8y=x24{{y}^{2}}+8y={{x}^{2}}?
In this question if we think then we have to calculate the dydx\dfrac{dy}{dx}, then in the first look it will look like a hard question but it is very easy. If we take the derivatives from here, then,
ddx(4y2+8y)=ddx(x2) 4ddx(y2)+8ddx(y)=2x \begin{aligned} & \Rightarrow \dfrac{d}{dx}\left( 4{{y}^{2}}+8y \right)=\dfrac{d}{dx}\left( {{x}^{2}} \right) \\\ & \Rightarrow 4\dfrac{d}{dx}\left( {{y}^{2}} \right)+8\dfrac{d}{dx}\left( y \right)=2x \\\ \end{aligned}
Now, again yy is the function of xx, so we use the chain rule for any derivatives involving yy. So, we get,
4ddx(y2)+8ddx(y)=2x 4.2ydydx+8dydx=2x 8y.dydx+8dydx=2x \begin{aligned} & 4\dfrac{d}{dx}\left( {{y}^{2}} \right)+8\dfrac{d}{dx}\left( y \right)=2x \\\ & \Rightarrow 4.2y\dfrac{dy}{dx}+8\dfrac{dy}{dx}=2x \\\ & \Rightarrow 8y.\dfrac{dy}{dx}+8\dfrac{dy}{dx}=2x \\\ \end{aligned}
Now, take dydx\dfrac{dy}{dx} common from L.H.S, we get,
dydx(8y+8)=2x dydx=2x8y+8 dydx=x4(y+1) \begin{aligned} & \dfrac{dy}{dx}\left( 8y+8 \right)=2x \\\ & \Rightarrow \dfrac{dy}{dx}=\dfrac{2x}{8y+8} \\\ & \Rightarrow \dfrac{dy}{dx}=\dfrac{x}{4\left( y+1 \right)} \\\ \end{aligned}
So, here the differentiation of 4y2+8y=x24{{y}^{2}}+8y={{x}^{2}} is done. And here dydx\dfrac{dy}{dx} is the Leibniz notation which is the first derivative of the function.
In the Leibniz notation which we derive from the use of a capital letter Δ\Delta to indicate the finite increments in variable quantity. If the function ff is differentiable at xx and we set y=f(x)y=f\left( x \right), then the derivative f(x)f'\left( x \right) is defined as f(x)=dydx=limΔx0ΔyΔx=limh0f(x+h)f(x)hf'\left( x \right)=\dfrac{dy}{dx}=\displaystyle \lim_{\Delta x \to 0}\dfrac{\Delta y}{\Delta x}=\displaystyle \lim_{h \to 0}\dfrac{f\left( x+h \right)-f\left( x \right)}{h}.
Thus, Leibniz notation is explained.

Note: During solving any problem of differentiation we always use Δ\Delta if the increments are infinite. But if the increment is very small or we can say that the limit of Δ\Delta or Δx\Delta x goes to zero, then it will be represented by dd or dxdx. And it is the form of Leibniz notation.