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Chemistry Question on Law Of Chemical Equilibrium And Equilibrium Constant

What is Kc for the following equilibrium when the equilibrium concentration of each substance is: [SO2]= 0.60 M, [O2] = 0.82 M and [SO3] = 1.90 M ?
2SO2(g)+O2(g)⇋2SO3(g)2SO_2(g) + O_2(g) ⇋ 2SO_3(g)

Answer

The equilibrium constant (Kc) for the give reaction is:
Kc=[SO3]2[SO2]2[O2]K_c =\frac {[SO_3]^2}{[SO_2]^2[O_2]}

Kc=(1.90)2M2(0.60)2(0.821)M3K_c= \frac {(1.90)^2 M^2}{(0.60)^2(0.821) M^3 }

Kc=12.239 M−1K_c = 12.239 \ M^{-1} (approximately)

Hence, Kc for the equilibrium is 12.239 M-1.