Solveeit Logo

Question

Question: What is \({K_p}\)? What goes on in a \({K_p}\)equation?...

What is Kp{K_p}? What goes on in a Kp{K_p}equation?

Explanation

Solution

We have to know that the forward and reverse reactions have the same rate when a reaction is in equilibrium. And as the forward and backward reactions continue, the concentrations of the reaction components remain stable at equilibrium. A chemical reaction's equilibrium constant is the value of its reaction quotient at chemical equilibrium, a condition reached by a dynamic chemical mechanism after a period of time has passed in which its structure shows no discernible propensity to alter.

Complete answer:
We need to remember that the ratio of concentrations at equilibrium for a reaction at a given temperature is described by equilibrium constants. In general, the letters KK or Kc{K_c} are used. Both concentrations are expressed in terms of molar concentration, as shown by the subscript c. When a reaction component is a gas, the sum of the chemical at equilibrium can also be expressed in terms of its partial pressure. When the equilibrium constant is expressed in terms of partial pressure, the expression for the equilibrium constant is Kp{K_p}. Hence Kp{K_p} is the equilibrium constant expressed in terms of its partial pressure.
For a generic balanced gas-phase equation as given below,
aA(g)+bB(g)cC(g)+dD(g)aA\left( g \right) + bB\left( g \right) \rightleftharpoons cC\left( g \right) + dD\left( g \right)
In this equation, a moles of reactant A reacts with b moles of reactant B to give c moles of product C and d moles of product D.
If we know the partial pressures for each component at equilibrium, where the partial pressure of A(g)A(g) is abbreviated as PA{P_A}, then
Kp=(PC)c(PD)d(PA)a(PB)b{K_p} = \dfrac{{{{({P_C})}^c}{{({P_D})}^d}}}{{{{({P_A})}^a}{{({P_B})}^b}}}
This is the equation for Kp{K_p}.

Note:
When we measure Kp{K_p}, keep the following points in mind. The reaction must be balanced. Otherwise, the equilibrium constant's stoichiometric coefficients and exponents would be wrong. In the equilibrium term, pure liquids or solids have a concentration of 11. This is the same as when you're figuring out Kc{K_c}. Kp{K_p} is often written without the use of units. The units for all partial pressures used to calculate Kp{K_p} should be the same.