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Question

Physics Question on Units and measurement

What is dimensional formula of thermal conductivity?

A

[MLT−1θ−1][ MLT^{ - 1} \theta^{ - 1} ]

B

[MLT−3θ−1][ MLT^{ - 3} \theta^{ - 1} ]

C

[M2LT−3θ−2][ M^2LT^{ - 3} \theta^{ - 2} ]

D

[ML2T−2θ][ ML^2T^{ - 2} \theta]

Answer

[MLT−3θ−1][ MLT^{ - 3} \theta^{ - 1} ]

Explanation

Solution

ΔQ=KA(T1−T2L)Δt\Delta Q = KA \left( \frac{ T_1 - T_2 }{ L } \right) \Delta t
or [ K ] = [ML2T−2][L][L2][θ][T]\frac{ [ ML^2 T^{ - 2} ] [ L ] }{ [ L^2 ] [ \theta ] [ T ] }
[MLT−3θ−1][ MLT^{ - 3} \theta^{ - 1} ]