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Question: What is derivative of \(\ln \left( 8x \right)\) ?...

What is derivative of ln(8x)\ln \left( 8x \right) ?

Explanation

Solution

Here in this question we have been asked to find the value of the derivative of the given logarithmic function ln(8x)\ln \left( 8x \right). Firstly we will assume 8x=u8x=u and then we will find the derivative of the given expression using the basic rule dydududx=dydx\dfrac{dy}{du}\dfrac{du}{dx}=\dfrac{dy}{dx} where yy is a function of uu and uu is a function of xx . We also know that ddxlnx=1x\dfrac{d}{dx}\ln x=\dfrac{1}{x}.

Complete step-by-step solution:
Now considering from the question we have been asked to find the value of the derivative of the given logarithmic function ln(8x)\ln \left( 8x \right).
From the basic concepts of the derivatives we know the basic rule given as dydududx=dydx\dfrac{dy}{du}\dfrac{du}{dx}=\dfrac{dy}{dx} where yy is a function of uu and uu is a function of xx .
We also know that ddxlnx=1x\dfrac{d}{dx}\ln x=\dfrac{1}{x}.
Let us assume that 8x=u8x=u and simplify the given expression. By using our assumption we will have ddxln(8x)=ddxln(u)\Rightarrow \dfrac{d}{dx}\ln \left( 8x \right)=\dfrac{d}{dx}\ln \left( u \right) .
Now by using the basic rule dydududx=dydx\dfrac{dy}{du}\dfrac{du}{dx}=\dfrac{dy}{dx} we will have ddxln(u)=dduln(u)dudx\Rightarrow \dfrac{d}{dx}\ln \left( u \right)=\dfrac{d}{du}\ln \left( u \right)\dfrac{du}{dx} .
Now by further simplifying this expression using ddxlnx=1x\dfrac{d}{dx}\ln x=\dfrac{1}{x} we will have dduln(u)dudx=1ududx\Rightarrow \dfrac{d}{du}\ln \left( u \right)\dfrac{du}{dx}=\dfrac{1}{u}\dfrac{du}{dx} .
Now by replacing u=8xu=8x we will get 1ududx=18xd(8x)dx\Rightarrow \dfrac{1}{u}\dfrac{du}{dx}=\dfrac{1}{8x}\dfrac{d\left( 8x \right)}{dx}.
Finally we will end up having
18xd(8x)dx=18x8 1x \begin{aligned} & \Rightarrow \dfrac{1}{8x}\dfrac{d\left( 8x \right)}{dx}=\dfrac{1}{8x}8 \\\ & \Rightarrow \dfrac{1}{x} \\\ \end{aligned}
Therefore we conclude that the value of the derivative of ln(8x)\ln \left( 8x \right) is given as 1x\dfrac{1}{x}.

Note: During the process of answering questions of this type we should be sure with the concepts that we are going to apply in between the steps. We can derive a simple conclusion from this question as follows ddxln(ax)=1x\dfrac{d}{dx}\ln \left( ax \right)=\dfrac{1}{x} where aa can be any integer and simple answer any other questions of this type using this conclusion.