Question
Question: What is \(cis\;0\)?...
What is cis0?
Solution
Euler’s law provides us that “any real number x, eix=cosx+isinx”
Where, e= base of natural logarithm
i= imaginary unit
x= angle in radians
This complex exponential function is sometimes expressed as cisx(“cosine plus I sine”). If xis a complex number, the formula still remains valid.
We can use trigonometric values to express the real and imaginary portions of an associated complex number.
In the standard (rectangular) form, a complex number would be expresseda+ib. However, on a complex number plane, the 'a' (real value) is corresponding with the x-axis and the 'b' (imaginary value) is corresponding with the y-axis. Therefore, any complex number (expressed as a coordinate pair on the plane) can be identified by its distance from the origin, r, and its vector, or angle, θ, above the positive x-axis.
Essentially, the coordinates (a,b) which express a complex number, are further converted into a polar equivalent, (r,θ) .
In this way, all complex numbers can be expressed as:
a+bi=r⋅cis(θ) Where: a=r⋅cos(θ)and b=r⋅sin(θ)
Therefore, r=a2+b2 and θ=arctan(ab)
Complete step-by-step answer:
So, here we are going to use Euler’s formula:
eix=cosx+isinx
The LHS of a equation can be written as cisx.
So, cisx=cosx+isinx
Now as per our question, we have to find the value of cis0.
So, here we have x=0
By substituting the above value of xinto the expression, we get:
⇒cis0=cos0+isin0
We are already aware that the value of cos0=1and sin0=0.
So, now substituting these values in the above equation, we get
⇒cis0=1+i(0)=1
So, the value of cis0 is 1.
Note: While using Euler’s formula be careful what to substitute in cisand always keep sinx as imaginary if you keep cosx you may lead to wrong answer.
In some of the problems you may need to just directly use eixinstead of using cis.
In addition to its application as a fundamental mathematical result, Euler's formula has many other uses in the world of physics and engineering.