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Question

Question: What is \(cis\;0\)?...

What is cis  0cis\;0?

Explanation

Solution

Euler’s law provides us that “any real number xx, eix=cosx+isinx{e^{ix}} = \cos x + i\sin x
Where, ee= base of natural logarithm
ii= imaginary unit
xx= angle in radians
This complex exponential function is sometimes expressed as cis  xcis\;x(“cosine plus I sine”). If xxis a complex number, the formula still remains valid.
We can use trigonometric values to express the real and imaginary portions of an associated complex number.
In the standard (rectangular) form, a complex number would be expresseda+iba + ib. However, on a complex number plane, the 'a' (real value) is corresponding with the x-axis and the 'b' (imaginary value) is corresponding with the y-axis. Therefore, any complex number (expressed as a coordinate pair on the plane) can be identified by its distance from the origin, r, and its vector, or angle, θ, above the positive x-axis.
Essentially, the coordinates (a,b) which express a complex number, are further converted into a polar equivalent, (r,θ) .
In this way, all complex numbers can be expressed as:
a+bi=rcis(θ)a + bi = r \cdot cis(\theta ) Where: a=rcos(θ)a = r \cdot cos(\theta )and b=rsin(θ)b = r \cdot sin(\theta )
Therefore, r=a2+b2r = \sqrt {{a^2} + {b^2}} and θ=arctan(ba)\theta = arctan\left( {\dfrac{b}{a}} \right)

Complete step-by-step answer:
So, here we are going to use Euler’s formula:
eix=cosx+isinx{e^{ix}} = \cos x + i\sin x
The LHS of a equation can be written as cis  xcis\;x.
So, cis  x=cosx+isinxcis\;x = \cos x + i\sin x
Now as per our question, we have to find the value of cis  0cis\;0.
So, here we have x=0x = 0
By substituting the above value of xxinto the expression, we get:
cis  0=cos0+isin0\Rightarrow cis\;0 = \cos 0 + i\sin 0
We are already aware that the value of cos0=1\cos 0 = 1and sin0=0\sin 0 = 0.
So, now substituting these values in the above equation, we get
cis  0=1+i(0)=1\Rightarrow cis\;0 = 1 + i\left( 0 \right) = 1
So, the value of cis  0cis\;0 is 11.

Note: While using Euler’s formula be careful what to substitute in ciscisand always keep sinx\sin x as imaginary if you keep cosx\cos x you may lead to wrong answer.
In some of the problems you may need to just directly use eix{e^{ix}}instead of using ciscis.
In addition to its application as a fundamental mathematical result, Euler's formula has many other uses in the world of physics and engineering.