Question

What is (are) number $(s)$ of unpaired electrons in the square planar $[Pt(CN)_4]^{2-}$ ion?

• A. 0
• B. 1
• C. 4
• D. 6

Answer 1

Answer: (D)

6

Answer 2

Outer electronic configuration of $Pt$ is $5 d^{9} 6 s^{1}$
Outer electronic configuration of $P t^{2+}$ is $5 d^{8}$.
As $C N^{-}$is strong field ligand, so pairing will take place.