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Question: What is \(\arccos (0.921)\)?...

What is arccos(0.921)\arccos (0.921)?

Explanation

Solution

Generally in Mathematics, the inverse trigonometric functions are known as arcus function which is the inverse function of the trigonometric function. In particular, they are the inverses of the sine, cosine, tangent, cotangent, secant, and cosecant functions. The most common notation to denote these inverse trigonometric functions are by prefixing an arc before the trigonometric function (i.e.)arcsin(x)arcsin\left( x \right) ,arccos(x)arccos\left( x \right) , arctan(x)arctan\left( x \right), arc sec(x){\text{ }}arc{\text{ }}sec\left( x \right) and so here, our question is to find arccos(x)arccos\left( x \right). As we discussed earlier, arccos(x)arccos\left( x \right) can also be written as cos1x{\cos ^{ - 1}}x.

Complete step by step answer:
Thearccos(x)arccos\left( x \right)is an inverse function of the cosine of xx when xx lies between 1 - 1and 11 (i.e.) 1x1 - 1 \leqslant x \leqslant 1. When cosy\cos y is equal to xx (i.e.) cosy=x\cos y = x. Then the arccosine of xx is equal to the inverse function of the cosine of xx, that is equal to yy.
arccos(x)=cos1x=yarccos\left( x \right) = {\cos ^{ - 1}}x = y

Here, the inverse cosine function does not mean cosine to the power of 1 - 1.From the above explanation, we can easily understand that arccos(x)arccos\left( x \right)can be found by looking at the value of xx in the logarithmic tables. That is, we need to look at the value of xxi n the natural cosine table, and then our required answer will be obtained.

Now, let us move on to our question.We need to find the value of arccos(0.921)\arccos (0.921).Here, xx is 0.9210.921. Now, let us look at the value of 0.9210.921 in the natural cosine table. Then,
arccos(0.921)=22551\arccos (0.921) = 22^\circ {55^1}
We need to convert the above degrees and minutes into decimal format. Now,
551=(5560){55^1} = {\left( {\dfrac{{55}}{{60}}} \right)^\circ }
Just divide the value of minutes by 6060so that we can obtain the decimal form.
And then, add 22{22^\circ }with (5560){\left( {\dfrac{{55}}{{60}}} \right)^\circ }.
22+551=22+(5560){22^\circ } + {55^1} = {22^\circ } + {\left( {\dfrac{{55}}{{60}}} \right)^\circ }
22+551=(22.92)\Rightarrow {22^\circ } + {55^1} = {\left( {22.92} \right)^\circ }

Hence, arccos(0.921)=22551=(22.92)\arccos (0.921) = 22^\circ {55^1} = {\left( {22.92} \right)^\circ }.

Note: The arccos(x)arccos\left( x \right)can be found by looking at the value of xx in the logarithmic tables. We can also ask to calculate the value of arcsin(x)arcsin\left( x \right), arctan(x)arctan\left( x \right). Similarly, the values of remaining inverse trigonometric functions such as arcsin(x)arcsin\left( x \right), arctan(x)arctan\left( x \right) can be calculated by using the above method.