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Question

Physics Question on Motion in a plane

What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, g=10m/s2g = 10\,m/s^{-2}) of an air-craft flying at a speed of 400m/s400\,m/s through a circular arc of radius 0.6km0.6\,km ?

A

26.726.7

B

16.916.9

C

13.513.5

D

30.230.2

Answer

26.726.7

Explanation

Solution

Here, v=400ms1v = 400 \,m \,s^{-1},
r=0.6km=0.6×103mr = 0.6 \,km = 0.6 \times 10^3\,m,
g=10ms2g = 10\, m s^{-2}
Centripetal acceleration,
ac=v2ra_{c}=\frac{v^{2}}{r}
(400ms1)20.6×103m\frac{\left(400\,m\,s^{-1}\right)^{2}}{0.6\times10^{3}\,m}
=26.7×103ms2=26.7\times10^{3}\,ms^{-2}
In the units of g(=10ms2)g(= 10 \,m s^{-2}), the centripetal acceleration is 26.726.7.