Question

What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, g = 10 m s^-2) of an air-craft flying at a speed of $400ms^{- 1}$through a circular arc of radius 0.6 km?

• A. 26.7
• B. 16.9
• C. 13.5
• D. 30.2

Answer 1

Answer: (A)

26.7

Answer 2

Here , $v = 400ms^{- 1}$

$r = 0.6km = 0.6 \times 10^{3}m$

$g = 10ms^{- 2}$

Centripetal accelerations,

$a_{c} = \frac{v^{2}}{r} = \frac{(400ms^{- 1})^{2}}{0.6 \times 10^{3}m} = \frac{16 \times 10^{4}m^{2}s^{- 2}}{0.6 \times 10^{3}m} = \frac{16 \times 10}{0.6}ms^{- 2} = 26.7 \times 10ms^{- 2}$

In the units of g ($= 10ms^{- 2}$), the centripetal accelerations is $26.7.$