Question

What is an example of a percent composition practice problem?

Answer 1

The percent structure mentions to you by mass what percent of every component is available in a compound. A synthetic compound is the blend of at least two components. On the off chance that you are examining a synthetic compound, you might need to discover the percent piece of a specific component inside that substance compound.

Complete step by step answer:
We have to know, to calculate the percent composition, the rule for calculating the percent composition has to be given,
- Track down the molar mass of the multitude of components in the compound in grams per mole.
- Track down the atomic mass of the whole compound.
- Divide the part's molar mass by the whole atomic mass.
- You will presently have a number somewhere in the range of $0$ and $1$ . Increase it by $100$ percentage to get percent arrangement.
We have to know the formula for calculating mass percent has to be given,
${\text{Mass percent = }}\dfrac{{{\text{Mass of element}}}}{{{\text{Total mass of compound}}}} \times {\text{ 100\% }}$
Example for calculating for percent composition of sugar, $({C_{12}}{H_{22}}{O_{11}})$
For,
The mass of carbon is $(12 \times 12.01){\text{ = 144}}{\text{.13g/mol}}$
The mass of hydrogen is $(22 \times 1.0079){\text{ = 22}}{\text{.17g/mol}}$
The mass of oxygen is $(11 \times 15.999){\text{ = 175}}{\text{.99g/mol}}$
Therefore,
The total mass of sugar is $342.29g/mol$ .
Now we applying each element value in the above mass percent formula,
The percent composition of carbon is \dfrac{{144.13g/mol}}{{342.29g/mol}} \times 100\% {\text{ = 42}}{\text{.1% }}
The percent composition of hydrogen is \dfrac{{22.17g/mol}}{{342.29g/mol}} \times 100\% {\text{ = 6}}{\text{.5% }}
The percent composition of oxygen is \dfrac{{175.99g/mol}}{{342.29g/mol}} \times 100\% {\text{ = 51}}{\text{.4% }}
Hence, the percent composition of sugar has to be determined.

Note: We would follow a similar method to discover the percent piece of any substance however, we need to know the amount of every individual segment you have and the complete mass.