Question

What is an example of a combined gas law practice problem?

Answer 1

We have to know the combined gas law consolidates the three gas laws. They are Boyle's Law, Gay-Lussac's Law, and Charles' Law. It expresses that the proportion of the result of pressing factor and volume and the supreme temperature of a gas is equivalent to a steady. The consistent k is a genuine steady if the quantity of moles of the gas does not change.

Complete step by step answer:
The one example of combined gas law has to be given,
The volume of a gas-filled balloon is $30L$ at $40^\circ C$ and $1.75atm$ of pressure. What volume will the balloon have at standard temperature and pressure?
We have to know the given details,
For pressure,
Initial pressure, ${P_1} = 1.75atm$
Final pressure, ${P_2} = 1.00atm$
For temperature,
Converting degree celsius to kelvin,
Initial temperature, ${T_1} = 40^\circ C = 313K$
Final temperature, ${T_2} = 0^\circ C = 273K$
For volume,
Initial volume, ${V_1} = 30L$
To calculate the final volume ${V_2}$,
We have to know the combined gas law formula, that is,
$\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{{P_2}{V_2}}}{{{T_2}}}$
Then, rewrite the above equation,
${V_2} = \dfrac{{{P_1}{V_1}{T_2}}}{{{T_1}{P_2}}}$
Now, applying given values in the above equation,
${V_2} = \dfrac{{1.75atm \times 30L \times 273K}}{{313K \times 1.00atm}}$
Therefore,
The volume ${V_2} = 45.8L$.

Note: We have to know the genuine illustration of the joined gas law applies to scuba jumping. In scuba jumpers, the human lungs are the holder that holds the gas. The pressing factor in water is more noteworthy than the pressing factor in air, and water pressure increments with profundity. With each extra foot that jumpers plunge, the water pressure rises.The consolidated gas law can be utilized to clarify the mechanics where pressing factor, temperature, and volume are influenced. For instance, climate control systems, coolers and the arrangement of mists and furthermore use in liquid mechanics and thermodynamics.