Question
Question: What is A in the given diagram?  is more electronegative than carbon-(2) because a CH2 group is present on carbon-(2) which decreases its electronegativity due to the +I effect. Hence, H+ ion will attack on the carbon-(1) and formation of a carbocation will take place as an intermediate.
The reaction is as follows:
Step-3: Hydride shift of the carbocation:
As the positive ion will be more stable on the carbon atom which is directly attached to the benzene ring because of resonance. So, the hydride shift of the carbocation will take place to form a more stable intermediate. The reaction is as follows:
Step-4: Attack of chlorine ion:
The chlorine ion attacks the most stable carbocation intermediate and the major product is formed after the reaction as follows:
Hence, the major product formed i.e., A is 1-chloro-1-phenylethane.
Note:
It is important to note that, in this case hydride shifts take place because of the presence of a benzene ring which provides extra stability to the carbocation due to resonance. In general cases, the hydride shift takes place to the carbon atom with higher degree.