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Question: What happens when diborane reacts with lewis bases?...

What happens when diborane reacts with lewis bases?

A

It forms boron trihydride (BH3)(BH_{3}) due to cleavage.

B

It undergoes cleavage to give borane adduct BH3LBH_{3}L (where, L = Lewis base)

C

It oxidizes to give B2O3B_{2}O_{3}

D

It does not react with Lewis bases.

Answer

It undergoes cleavage to give borane adduct BH3LBH_{3}L (where, L = Lewis base)

Explanation

Solution

: B2H6+2NMe32BH3.NMe3B_{2}H_{6} + 2NMe_{3} \rightarrow 2BH_{3}.NMe_{3}

or B2H6+2L(Lewisbase)2BH3Adduct.LB_{2}H_{6} + \underset{\begin{aligned} & (Lewisbase) \\ & \end{aligned}}{2L} \rightarrow \underset{\begin{aligned} & Adduct \\ & \end{aligned}}{2BH_{3}}.L