Question

What happens when $CC{l_4}$ is treated with the $AgN{O_3}$ solution?
(A) $N{O_2}$ will be evolved
(B) A white ppt. of AgCl will form
(C) $CC{l_4}$ will dissolve in $AgN{O_3}$ solution
(D) nothing will happen

Answer 1

Carbon tetrachloride ( $CC{l_4}$ ) is a non polar inert solvent. The only purpose is to use these inert solvent to dissolve the reactants present in the reaction. $B{r^ + }$ attacks as an electrophile on alkene and undergoes electrophilic addition reaction.

Complete Step By Step Answer:
Carbon tetrachloride does not ionize in the solution because it is a covalent compound.No ion exchange between $CC{l_4}$ and silver nitrate $AgN{O_3}$ , no reaction will take place.
Electrophiles are electron deficient species and can accept an electron pair from electron rich species. Examples include carbocations and carbonyl compounds. A nucleophile is an electron rich species and donates electron pairs to electron deficient species. Examples include carbanions, water , ammonia, cyanide ion etc
$CC{l_4}$ is an electrophile because chlorine has vacant d orbitals and thus are attracted to an electron rich centre.Most electrophiles other than $CC{l_4}$ have positive charge over them. and has a tendency to accept electrons and as solvent because it has no positive charge OR negative charge .
AgCl is very poorly soluble. As chloride ions form, they precipitate out as the silver salt, driving the reaction forward through Le Chatlier's principle.
Ethanol is a pretty crummy nucleophile, without silver this reaction probably will reach an equilibrium at just a few percent of the new alkyl alcohol created. A tertiary electrophile favors $S{N^1}$ , while a primary electrophile favors $S{N^1}$ .For the $S{N^1}$ reactions, the $1\%$ ethanolic silver nitrate was used. It is protic, in that a hydrogen ion could be donated. For the $S{N^2}$ , an aprotic solvent was used (NaI in acetone), in that no hydrogen ion could be donated.
For $S{N^1}$ reactions, $AgN{O_3}$ in EtOH is chosen because nitrate ion is a weak nucleophile and EtOH is a polar protic solvent favoring a $S{N^1}$ mechanism. The AgBr and AgCl formed in this reaction are insoluble in EtOH, so that the time to produce a cloudy solution can be compared.
$CC{l_4}$ is a covalent compound, so it does not react with $AgN{O_3}$
The correct answer is “D” .i.e. nothing will happen.

Note:
$CC{l_4}$ is merely the solvent and in these cases has no effect on the reaction (unlike when water or alcohols are the solvent) as it does not react with the reactants and interfere in the reaction mechanism. Ionic compounds mean the compounds that were formed from the atoms with ionic electronegativity. The basic rule of solubility states that it dissolves in like nature which reveals that ionic compounds like silver nitrate cannot be able to dissolve in nonpolar solvent like carbon tetrachloride.