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Question

Question: What happened when: \(B{{F}_{3}}\) is reacted with ammonia?...

What happened when:
BF3B{{F}_{3}} is reacted with ammonia?

Explanation

Solution

The BF3B{{F}_{3}} is a Lewis acid i.e. an electron deficient species and NH3N{{H}_{3}} is a Lewis base, a species which consists of lone pairs that can be donated for the formation of bonds.
- NH3N{{H}_{3}} molecule consists of a lone pair of electrons .

Complete Solution :
So here in the question we are asked to predict what happens when NH3N{{H}_{3}} and BF3B{{F}_{3}} reacts together.
Before predicting the product let’s see some characteristics of ammonia and boron trifluoride.
So in BF3B{{F}_{3}} molecule B is the central atom and we know that theBF3B{{F}_{3}} is a Lewis acid i.e. an electron deficient species.
- The atomic number of B is 5 and has an electronic configuration:
E.CofB=1s22s22p1\text{E}\text{.C}\,\text{of}\,\text{B=1}{{\text{s}}^{\text{2}}}\text{2}{{\text{s}}^{\text{2}}}\text{2}{{\text{p}}^{\text{1}}}
- The valency possessed by the B atom is +3.
- The hybridization of BF3B{{F}_{3}} molecule is sp2s{{p}^{2}} and hence having a planar structure.
- In NH3N{{H}_{3}} molecule, N is the central atom having the atomic number 7 and the electronic configuration is,
E.CofN=1s22s22p3\text{E}\text{.C}\,\text{of}\,\text{N=1}{{\text{s}}^{\text{2}}}\text{2}{{\text{s}}^{\text{2}}}\text{2}{{\text{p}}^{\text{3}}}
Ammonia is a sp3s{{p}^{3}} hybridized molecule in which one lone pair is present and hence having a trigonal pyramidal structure.
So as we discussed earlier BF3B{{F}_{3}} is a Lewis acid and requires two electrons for B to obtain the octet configuration and NH3N{{H}_{3}} consists of one lone pair of electron and it acts as the Lewis base according to Lewis theory.
Hence the NH3N{{H}_{3}} molecule donates its lone pair of electrons to the BF3B{{F}_{3}} molecule and forms a coordinate bond.
So the ammonia and boron trifluoride on reactions forms an adduct.

NH3N{{H}_{3}} The hybridization of this adduct formed is sp3s{{p}^{3}} hybridized adduct.

Note: The hybridization of a molecule is calculate using the formulae,
steric number = No. of bps + No.of lps\text{steric number = No}\text{. of bps + No}\text{.of lps}
Bps refers to bond pairs and lps refers to lone pairs and the steric number obtained will give an idea about the hybridization of the molecule.