Question

What are X and Y in the reaction ${{C}_{2}}{{H}_{4}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{80{{\,}^{o}}C}X({{H}_{2}}O./\Delta a)Y$

• A. ${{C}_{2}}{{H}_{6}},{{C}_{2}}{{H}_{5}}OH$
• B. ${{C}_{2}}{{H}_{2}},{{C}_{2}}{{H}_{5}}SH$
• C. ${{C}_{2}}{{H}_{5}}OS{{O}_{3}}H,{{C}_{2}}{{H}_{5}}OH$
• D. ${{C}_{2}}{{H}_{2}},C{{H}_{3}}CHO$

Answer 1

Answer: (C)

${{C}_{2}}{{H}_{5}}OS{{O}_{3}}H,{{C}_{2}}{{H}_{5}}OH$

Answer 2

${{C}_{2}}{{H}_{4}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{80{{\,}^{o}}C}X\xrightarrow{{{H}_{2}}O\Delta }Y$ Ethylene reacts with ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ to form ethyl hydrogen sulphate as $\text{ }\underset{C{{H}_{2}}}{\overset{C{{H}_{2}}}{\mathop{\text{ }\\!\\!|\\!\\!\text{ }\\!\\!|\\!\\!\text{ }}}}\,+HHS{{O}_{4}}\xrightarrow{{}}\underset{(X)}{\mathop{\underset{C{{H}_{2}}HS{{O}_{4}}}{\overset{C{{H}_{3}}}{\mathop{|}}}\,}}\,$ So, X is ethyl hydrogen sulphate and X (Ethyl hydrogen sulphate) on hydrolysis gives ethyl alcohol and ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ is regenerated as - $\underset{C{{H}_{2}}HS{{O}_{4}}+HOH}{\overset{C{{H}_{3}}}{\mathop{|}}}\,\xrightarrow{\Delta }\underset{\begin{smallmatrix} \text{Ethyl}\,\text{alcohol} \\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\text{(}\gamma \text{)} \end{smallmatrix}}{\mathop{\underset{C{{H}_{2}}OH}{\overset{C{{H}_{3}}}{\mathop{|}}}\,}}\,+{{H}_{2}}S{{O}_{4}}$ So, the Y is ethyl alcohol.