Question
Question: What are two examples of convergent sequences?...
What are two examples of convergent sequences?
Solution
We solve this problem by using the definition of convergence and some tests used to find the convergence. There are mainly 2 tests we use for writing the examples of convergent sequences.
(1) p – series test:
If the sequence in the form ∑np1 then,
If p<1 then the sequence converges and if p≥1 then the sequence diverges.
(2) Root test:
If the nth term of a sequence is an and l=n→∞limn∣an∣
If l<1 then the sequence converges and if l≥1 then the sequence diverges.
Complete step by step answer:
We are asked to give two examples of convergent sequences.
Let us use two tests for convergence to find the examples of convergent sequences.
First let us use the p – series test.
We know that the p – series test is given as,
If the sequence in the form ∑np1 then,
If p<1 then the sequence converges and if p≥1 then the sequence diverges.
Now, let us take an example where p<1 in the sequence ∑np1 then we get one example as ∑n1
Here, we can see that in ∑n1 the value of ′p′ is 21 which is less than 1.
Now, let us use the root test.
We know that the root test is given as,
If the nth term of a sequence is an and l=n→∞limn∣an∣
If l<1 then the sequence converges and if l≥1 then the sequence diverges.
Let us assume that the nth term of sequence as,
⇒an=3n1
Now, by using the root test to above sequence then we get,
⇒l=n→∞limn3n1⇒l=n→∞lim31=31
Here, we can see that the value of ′l′ is less than 1 so that the sequence is convergent.
Therefore, we can conclude that the two examples of convergent sequence are given as,
(1) ∑n1
(2) ∑3n1
Note: The main mistake is done in p – series test. The p – series test have the summation as ∑np1 then we can compare the value of ′p′ with respect to ‘1’ to get the nature of sequence.
But some students may take the p – series as ∑np and compare the value of ′p′ which gives the wrong answer.