Question
Question: What are the units of rate constant for the first order reaction?...
What are the units of rate constant for the first order reaction?
Solution
We know that rate of a reaction is explained as change in concentration of any of the reactants or product per unit time. For example:
aA + bB→cC + dD
Rate of reaction is equal to decrease in concentration of either A or B or increases in concentration of C or D per unit time. In the above reaction a, b, c, and d are stoichiometric coefficients. Thus rate for the above general reaction is equal to rate of removal of A or B per mole and also equal to rate appearance of C or D per mole. It can be shown is as follows:
rate=−a1dtd[A]=−b1dtd[B] =+c1dtd[C] = + d1dtd[D]
Here [ ] represents concentration in mole per liter and ‘d’ represents an infinitesimally small change in concentration. Negative sign shows that concentration of reactant A and B are decreasing whereas positive sign shows concentration of product C and D are increasing.
Complete step by step answer:
As we know a first order reaction is represented as
A→Product
Initial concentration: a 0
Concentration after time: (a−x) x
Now we put differential rate law:
−dtd(a−x)=+dtdx=k1(a−x)
On integrating above equation we get
Integration rate law:
k1=t2.303log(a−xa)
Here k1 is the rate constant of a first order reaction unit that is per time or s−1 since rest of the expression consists of numerical values and log does not have any units.
Thus, the unit of first order reaction is s−1 .
Note:
Rate of the reaction is proportional to the product of concentration of reactants, each raised to some power. i.e.
rate∝[A]m[B]n rate = k[A]m[B]n
Here k is rate constant. At all concentrations, rate constant k is equal to rate of a reaction.