Question

What are the units of $K = 1/4 \pi \varepsilon_{0}?$

• A. $C^2N^{-1}m^{-2}$
• B. $Nm^2C^{-2}$
• C. $Nm^2C^2$
• D. Unit less

Answer 1

Answer: (B)

$Nm^2C^{-2}$

Answer 2

From Coulomb's law two stationary point charges $q_{1}$ and $q_{2}$ attract or repel each other with a force $F$ which is directly proportional to the product of the charges and inversely proportional to the square of distance between them, i.e., $F=\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r^{2}}$ $\therefore K=\frac{1}{4 \pi \varepsilon_{0}}=\frac{F r^{2}}{q^{2}}$ (if $q_{1}=q_{2}=q )$ Hence, units of $K=\frac{ Nm ^{2}}{ C ^{2}}$ $= Nm ^{2} C ^{-2}$