Question

What are the units of equivalent conductivity of a solution?
(A) $mho\text{ }c{{m}^{-1}}$ $mho\text{ }c{{m}^{-1}}$
(B) $ohm\text{ }c{{m}^{-1}}\text{ }g\text{ }equi{{v}^{-1}}$
(C) $mho\text{ }c{{m}^{-2}}\text{ }g\text{ }equi{{v}^{-1}}$
(D) $oh{{m}^{-1}}\text{ c}{{\text{m}}^{2}}\text{ g equi}{{\text{v}}^{-1}}$

Answer 1

The conductance of a solution of different electrolytes varies with their concentration. To compare the conductance of different electrolytes. It is convenient to define a quantity which is called equivalent conductance.

Complete answer:
- The equivalent conductance can be defined as the net conductance of every ion that is produced from one gram equivalent of a given substance.
- If we consider two large parallel electrodes set 1 cm apart and the whole of the solution containing 1g equivalent of an electrolyte is placed between the electrodes. If V is the volume of the solution containing 1 g equivalent of an electrolyte. The equivalent conductivity is given as:
$\lambda =kV$
Where k is the specific conductance,
If C is concentration of the solution in $\left( g\text{ }equi\text{ }c{{m}^{-3}} \right)$, then we can write the relation of Volume to concentration, that is $volume=\dfrac{1}{concentration}$.
Hence, Then the equation is,
$\lambda =k\times \dfrac{1}{C}$
- $\lambda$ is never determined directly, but is calculated from its specific conductance and concentration.
- Specific conductance k is the reciprocal of specific resistance $\rho$ (it is the resistance offered by a material 1cm in length and having an area of cross section $1c{{m}^{2}}$). Specific resistance has unit ohm cm, specific conductance has unit of$oh{{m}^{-1}}\text{ }c{{m}^{-1}}$
-Hence we can see that the unit of equivalent conductance is found to be:
$\lambda =k\times \dfrac{1}{C}$

& \dfrac{oh{{m}^{-1}}c{{m}^{-1}}}{g\text{ equiv c}{{\text{m}}^{3}}} \\\ & =oh{{m}^{-1}}\text{ }g\text{ equi}{{\text{v}}^{-1}}\text{ c}{{\text{m}}^{2}}\text{ } \\\ \end{aligned}$$ Or we can write it as $oh{{m}^{-1}}\text{ c}{{\text{m}}^{2}}\text{ g equi}{{\text{v}}^{-1}}$ \- Hence we can conclude that the option (d) is the correct answer that is the equivalent conductivity has the unit $oh{{m}^{-1}}\text{ c}{{\text{m}}^{2}}\text{ g equi}{{\text{v}}^{-1}}$. **Additional information:** \- Experimental measurement of a solution is reciprocal of the resistance, therefore, the experimental determination of the conductance of a solution involves the measurement of its resistance. \- We have seen that conductivity k is the reciprocal of resistivity, that is $\rho $that is: $$\begin{aligned} & k=\dfrac{1}{\rho } \\\ & and\text{ }\rho \text{=R}\dfrac{a}{l} \\\ & k=\dfrac{1}{R}\left( \dfrac{1}{a} \right) \\\ & k=G\left( \dfrac{l}{a} \right) \\\ \end{aligned}$$ Where G is the conductance of the cell, l is the distance of separation of two electrodes, and $\dfrac{l}{a}$ cell constant. **Note:** \- We should not get confused in terms of specific and equivalent conductance. Specific conductance is denoted by symbol k and equivalent conductance is denoted by symbol $\lambda $ \- We can see that$\lambda $ is never determined directly, but always calculated from its specific conductivity and concentration.