Question

What are the formulae of stannous bromide and stannic bromide?

Answer 1

Tin is a soft metal with atomic number $50$ and bromine is a non-metal with atomic number $35$ . Metals and non-metals combine to form a compound known as salt. Based on the oxidation state of metal the name of the salts can be written. The metal with the highest oxidation state ends with the suffix -ic and the metal with lowest oxidation state ends with the suffix -ous.

Complete answer:
Periodic table consists of elements arranged in the increasing order of atomic numbers arranged in the vertical columns and horizontal rows. The vertical columns were known as groups and the horizontal rows were known as periods.
The elements belonging to group $17$ are known as halogens and exist as non-metallic. Metals and non-metals combine with each other to form a compound known as salt.
Tin is a chemical element with atomic number $50$ and bromine is a non-metal with atomic number $35$ combined to form salts like stannous bromide and stannic bromide.
Stannous bromide is a salt with molecular formula of $SnB{r_2}$ , the oxidation state of tin is $+ 2$
Stannic bromide is a salt with a molecular formula of $SnB{r_2}$ , the oxidation state of tin is $+ 4$ .

Note:
Bromine is the only non-metal that can exist as liquid at room temperature. The halogens have the oxidation state of $- 1$ as they generally try to gain one electron to attain the nearest inert or noble gas configuration. As $SnB{r_2}$ has a low oxidation state of $+ 2$ it is known as stannous bromide and in $SnB{r_2}$ the oxidation state of tin is $+ 4$ . Thus, it can be known as Stannic bromide