Question

What are the correct steps to convert aldehyde to acetone?
(a) $C{{H}_{3}}MgBr$,${{H}_{2}}O$, oxidation
(b) oxidation, $Ca{{(OH)}_{2}}$, heat.
(c) reduction, $KCN$, hydrolysis
(d) oxidation, ${{C}_{2}}{{H}_{5}}ONa$, heat.

Answer 1

We can convert aldehyde into acetone by first converting aldehyde into the acid and then treat that with metal hydroxide and compound so the form gives the acetone on warming. Now you can easily answer the given statement. Solve it.

Complete answer:
Acetaldehyde consists of two carbon atoms linked to each through the single bonds and contains $-CHO$ group as the functional group.
On the contrary, acetone consists of two carbon atoms out of which one carbon atom is linked to the oxygen atom through the double bond and contains $-C=O$ group as the functional group.
Now considering the statement:
To convert acetaldehyde to acetone, it is first reacted with the oxygen and results in the formation of the acid i.e. it undergoes oxidation and then, the acid so formed is made to react with the calcium hydroxide and the compound so formed when heated, results in the formation of the final product i.e. the acetone along with the removal of calcium carbonate.
The reaction is supposed to occurs as;
$C{{H}_{3}}CHO\xrightarrow{O}C{{H}_{3}}COOH\xrightarrow{Ca{{(OH)}_{2}}}{{(C{{H}_{3}}COO)}_{2}}Ca\xrightarrow[-CaC{{O}_{3}}]{Heat}C{{H}_{3}}COC{{H}_{3}}$
So, thus the correct steps to convert acetaldehyde to acetone is oxidation, $Ca{{(OH)}_{2}}$ and heat.

Hence, option (b) is correct.

Note:
The only difference between the aldehyde and ketone is that aldehyde consists of the $-CHO$ group as the functional group in its compounds whereas on the contrary the acetone consists of the $-C=O$ group as the functional group in its compounds.