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Question: What are the correct oxidations state, coordination number, configurations, magnetic character and m...

What are the correct oxidations state, coordination number, configurations, magnetic character and magnetic moment of K4[Mn(CN)6]K_{4}\lbrack Mn(CN)_{6}\rbrack?

O.S. C.N. Configu- Magnetic Magnetic

-ration Character moment

A

+6 6 t2g5t_{2g}^{5} Diamagnetic 0

B

+4 6 t2g4eg1t_{2g}^{4}e_{g}^{1} Paramagnetic 1.732B.M1.732B.M

C

+2 6 t2g5t_{2g}^{5} Paramagnetic 1.732B.M1.732B.M

D

+4 6 t2g3eg2t_{2g}^{3}e_{g}^{2} Diamagnetic 0

Answer

+2 6 t2g5t_{2g}^{5} Paramagnetic 1.732B.M1.732B.M

Explanation

Solution

O.S. +2, C.N. = 6, configurations =t25g= t_{2}^{5}g

Mn2+=4s03d5Mn^{2 +} = 4s^{0}3d^{5}

It has one unpaired electron and hence it is paramagnetic in nature.

μ=1(1+2)=3=1.732B.M.\mu = \sqrt{1(1 + 2)} = \sqrt{3} = 1.732B.M.