Question

What amount of water is added in $40\, ml$ of $NaOH (0.1\, N )$ which is neutralized by $50\, ml$ of $HCl (0.2\, N )$ ?

• A. 80 ml
• B. 60 ml
• C. 40 ml
• D. 90 ml

Answer 1

Answer: (B)

60 ml

Answer 2

Using Normality equation $N _{1} V _{1}= N _{2} V _{2}$ $0.1 \times V_{1}=0.2 \times 50$ $V_{1}=\frac{0.2 \times 50}{0.1}=100\, ml$ Total volume $= NaOH +$ water $100=40+x$ So amount of water added is $60\, ml$.