Question

What amount of $Cl_{2}$ gas liberated at anode, if $1$ ampere current is passed for $30$ minute from $NaCl$ solution?

• A. 0.66 mol
• B. 0.33 mol
• C. 0.66 g
• D. 0.33 g

Answer 1

Answer: (C)

0.66 g

Answer 2

$2 Cl ^{-} \rightarrow \underset{1 mole}{Cl _{2}}+\underset{2 \times 96500 \text{coulomb}}{2 e^{-}( At\, anode)}$
$Q =i t=1 \times 30 \times 60$
$=1800$ coulomb
The amount of chlorine liberated by passing 1800 coulomb of electric charge
$=\frac{1 \times 1800 \times 71}{2 \times 96500}=0.66\, g$