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Question

Question: Weight of a body of mass m decreases by 1% when it is raised to height h above the earth's surface. ...

Weight of a body of mass m decreases by 1% when it is raised to height h above the earth's surface. If the body is taken to a depth h in a mine, change in its weight is

A

2% decrease

B

0.5% decrease

C

1% increase

D

0.5% increase

Answer

0.5% decrease

Explanation

Solution

Percentage change in g when the body is raised to height hh , Δgg×100%=2h×100R=1%\frac { \Delta g } { g } \times 100 \% = \frac { 2 h \times 100 } { R } = 1 \%

Percentage change in g when the body is taken into depth d, d=hd = h]

∴ Percentage decrease in weight =12(2hR×100)=12(1%)=0.5%= \frac { 1 } { 2 } \left( \frac { 2 h } { R } \times 100 \right) = \frac { 1 } { 2 } ( 1 \% ) = 0.5 \% .