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Question: We have three aqueous solution of NaCl labeled as ‘A’, ‘B’ and ‘C’ with concentration \(0.1M,0.01\)M...

We have three aqueous solution of NaCl labeled as ‘A’, ‘B’ and ‘C’ with concentration 0.1M,0.010.1M,0.01M and 0.0010.001M, respectively the value of van’t Hoff factor for these solution will be in the order.

A

iA<iB<iCi_{A} < i_{B} < i_{C}

B

iA>iB>iCi_{A} > i_{B} > i_{C}

C

iA=iB=iCi_{A} = i_{B} = i_{C}

D

iA<iB>iCi_{A} < i_{B} > i_{C}

Answer

iA=iB=iCi_{A} = i_{B} = i_{C}

Explanation

Solution

As NaCl is a strong electrolyte, it undergoes dissociation completely. Thus van’t Hoff factor will be same for all these solutions, iA=iB=iCi_{A} = i_{B} = i_{C}