Solveeit Logo
Login

Question

Question: Wavelength of light used in an optical instrument are \(\lambda_{1} = 4000\)Å and \(\lambda_{2} = 50...

Wavelength of light used in an optical instrument are λ1=4000\lambda_{1} = 4000Å and λ2=5000\lambda_{2} = 5000Å, then ratio of their respective resolving power (corresponding to λ1\lambda_{1}and λ2)\lambda_{2}) is

A

16 : 25

B

9 : 1

C

4 : 5

D

5 : 4

Answer

5 : 4

Explanation

Solution

R.P. ∝1λ⇒(R.P.)1(R.P.)2=λ2λ1=54\propto \frac{1}{\lambda} \Rightarrow \frac{(R.P.)_{1}}{(R.P.)_{2}} = \frac{\lambda_{2}}{\lambda_{1}} = \frac{5}{4}