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Physics Question on Wave optics

Wavelength of light used in an optical instrument are λ1=4000A∘\lambda_1=4000A^\circ and λ2=5000A∘\lambda_2=5000A^\circ then ratio of their respective resolving powers (corresponding to λ1\lambda_1 and λ2\lambda_2 ) is

A

16:25

B

9:01

C

4:05

D

5:04

Answer

5:04

Explanation

Solution

R ∝1λR \, \propto \frac{1}{\lambda}