Question

Water rises in a vertical capillary tube upto a length of $10 \,cm$. If the tube is inclined at $45{}^\circ$ , the length of water column risen in the tube will be

• A. $10\,cm$
• B. $10\,\sqrt{2}\,cm$
• C. $5\,\sqrt{2}\,cm$
• D. $20\,cm$

Answer 1

Answer: (B)

$10\,\sqrt{2}\,cm$

Answer 2

When capillary tube is tilted through an angle $\theta$, then length of water risen in capillary, $l=\frac{h}{\cos \theta}$ Here $\theta=45^{\circ}$ $\therefore l=\frac{10}{\cos 45^{\circ}}=10 \sqrt{2} cm$