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Physics Question on Surface tension

Water rises in a capillary upto a extension height such that upward force of surface tension balances the force of 75×10−4 N75 \times 10^{-4} \,N due to weight of water. If surface tension of water is 6×10−2 N/m6 \times 10^{-2} \,N / m. The internal circumference of the capillary must be

A

12.5×10−2m12.5 \times 10^{-2} m

B

6.5×10−2m6.5 \times 10^{-2} m

C

0.50×10−2m0.50 \times 10^{-2} m

D

1.25×10−2m1.25 \times 10^{-2} m

Answer

12.5×10−2m12.5 \times 10^{-2} m

Explanation

Solution

The correct answer is A:12.5×10−2m12.5 \times 10^{-2} m
F=TLF =T L
L=FL=75×10−46×10−2L =\frac{F}{L}=\frac{75 \times 10^{-4}}{6 \times 10^{-2}}
=12.5×10−2m=12.5 \times 10^{-2} m