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Question: Water rises in a capillary tube to a certain height such that the upward force due to surface tensio...

Water rises in a capillary tube to a certain height such that the upward force due to surface tension is balanced by 75×104N75 \times 10^{- 4}N force due to the weight of the liquid. If the surface tension of water is 6×102N/m6 \times 10^{- 2}N/m, the inner circumference of the capillary must be

A

1.25×102m1.25 \times 10^{- 2}m

B

0.50×102m0.50 \times 10^{- 2}m

C

6.5×102m6.5 \times 10^{- 2}m

D

12.5×102m12.5 \times 10^{- 2}m

Answer

12.5×102m12.5 \times 10^{- 2}m

Explanation

Solution

Weight of liquid = upward force due to surface tension

75×104=2πrT75 \times 10^{- 4} = 2\pi rT

Circumference 2πr=75×104T=75×1046×102=0.1252\pi r = \frac{75 \times 10^{- 4}}{T} = \frac{75 \times 10^{- 4}}{6 \times 10^{- 2}} = 0.125

= 12.5×102m12.5 \times 10^{- 2}m