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Question: Water in a canal 1.5 m wide and 6 m deep is flowing with a speed of 10 Km/hr. How much area will it ...

Water in a canal 1.5 m wide and 6 m deep is flowing with a speed of 10 Km/hr. How much area will it irrigate in 30 minutes if 8 cm of standing water is desired?

Explanation

Solution

Hint: First find out the volume of water in the reservoir canal in a given time, then equate it to the volume which is to be irrigated, you will get your answer.

Complete step by step solution:

It is given that,

Breadth (b) = 1.5m, Depth or height (h) = 6m, Speed = 10Km/hr

\Rightarrow Length l of canal in 1 hour = 10Km

\Rightarrow Length l of canal in 30 minutes = 102Km=5Km\frac{{10}}{2}Km = 5Km

\Rightarrow Volume of canal is = lbh = 5000×1.5×6  m35000 \times 1.5 \times 6\;{m^3}

Volume of water in canal = Volume of area to be irrigated

                      5000×1.5×6=  Area irrigated × height\Rightarrow \;\;\;\;\;\;\;\;\;\;\;5000 \times 1.5 \times 6 = \;{\text{Area irrigated }} \times {\text{ height}}

Given: height = 8cm = 8100m\dfrac{8}{{100}}m

\Rightarrow Area irrigated = 5000×1.5×68100=5000×150×68\dfrac{{5000 \times 1.5 \times 6}}{{\frac{8}{{100}}}} = \dfrac{{5000 \times 150 \times 6}}{8}

\Rightarrow Area irrigated = 562500  m2562500\;{m^2}

So, this is your desired answer.

NOTE: - Just be careful with the formula you use. A good grasp over mensuration topics will be an added advantage to solve these problems.