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Question: Water enters through one end of a horizontal pipe of non-uniform cross-section with a velocity of 0....

Water enters through one end of a horizontal pipe of non-uniform cross-section with a velocity of 0.4m/s and leaves the other end with a velocity 0.6 m/s. The pressure of water at the first end is 1500N/m2. What is the pressure at the other end? (Density of water = 1.0103kg/m3)

A

1000N/m2

B

100N/m2

C

500 N/m2

D

1400 N/m2

Answer

1400 N/m2

Explanation

Solution

According to Bernoulli's theorem

P1 + 12ρv12\frac { 1 } { 2 } \rho v _ { 1 } ^ { 2 } = P2 +

Or, P1 – P2 =

Or, P2 = P112ρ(v22v12)\frac { 1 } { 2 } \rho \left( v _ { 2 } ^ { 2 } - v _ { 1 } ^ { 2 } \right)

Given : P1 = 1500n/m2, v1 = 0.4m/s, v2 = 0.6 m/s, P2 = ?

∴ P2 = 1500 – 12\frac { 1 } { 2 } 1103 [(0.6)2 – (0.4)2]

Or, P2 = 1500 – 100 = 1400 N/m2