Question
Question: Water enters through one end of a horizontal pipe of non-uniform cross-section with a velocity of 0....
Water enters through one end of a horizontal pipe of non-uniform cross-section with a velocity of 0.4m/s and leaves the other end with a velocity 0.6 m/s. The pressure of water at the first end is 1500N/m2. What is the pressure at the other end? (Density of water = 1.0103kg/m3)
A
1000N/m2
B
100N/m2
C
500 N/m2
D
1400 N/m2
Answer
1400 N/m2
Explanation
Solution
According to Bernoulli's theorem
P1 + 21ρv12 = P2 +
Or, P1 – P2 =
Or, P2 = P1 − 21ρ(v22−v12)
Given : P1 = 1500n/m2, v1 = 0.4m/s, v2 = 0.6 m/s, P2 = ?
∴ P2 = 1500 – 21 1103 [(0.6)2 – (0.4)2]
Or, P2 = 1500 – 100 = 1400 N/m2