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Question

Physics Question on Thermodynamics

Water boils in an electric kettle in 20 minutes after being switched on. Using the same main supply, the length of the heating element should be ………….. to …………. times of its initial length if the water is to be boiled in 15 minutes.

A

increased, 34\frac{3}{4}

B

increased, 43\frac{4}{3}

C

decreased, 34\frac{3}{4}

D

decreased, 43\frac{4}{3}

Answer

decreased, 34\frac{3}{4}

Explanation

Solution

The resistance of the heating element is:
R=ρA.R = \rho \frac{\ell}{A}.
The power is inversely proportional to the length:
P1.P \propto \frac{1}{\ell}.
From the relation P1×t1=P2×t2P_1 \times t_1 = P_2 \times t_2:
P1P2=t2t1=1520.\frac{P_1}{P_2} = \frac{t_2}{t_1} = \frac{15}{20}.
Substituting P1P \propto \frac{1}{\ell}:
21=t2t1=1520=34.\frac{\ell_2}{\ell_1} = \frac{t_2}{t_1} = \frac{15}{20} = \frac{3}{4}.
Thus, the new length should be decreased to:
2=341.\ell_2 = \frac{3}{4} \ell_1.