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Question: Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two differe...

Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two different values of constant pressure. What can be inferred about relation between P1 and P2 ?

A

P1 > P2

B

P1 = P2

C

P1 < P2

D

Data is insufficient

Answer

P1 > P2

Explanation

Solution

According to Charle’s law VTV \propto T

or VT\frac{V}{T}= constant = 1P\frac{1}{P}

As in graph, slope at P2P_{2}is more than slope at P1,P_{1},

P1>P2\therefore P_{1} > P_{2}