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Question

Physics Question on kinetic theory

Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two different values of constant pressure. What can be inferred about relation between P1P_1 and P2P_2 ?

A

P1>P2P_1 > P_2

B

P1=P2P_1 = P_2

C

P1<P2P_1 < P_2

D

data is insufficient

Answer

P1>P2P_1 > P_2

Explanation

Solution

According to Charles law VTV \propto T or VT=\quad \frac{V}{T} = constant =1P= \frac{1}{P} As in graph, slope at P2P_{2} is more than slope at P1P_{1}, P1>P2\therefore\quad P _{1} > P_{2}