Question

Volume strength of ${H_2}{O_2}$ is 5.6 its normality will be

Answer 1

Concentration of a solution is measured by normality. It is denoted by the symbol ‘N’. Normality of a base can be calculated by the below formula.
${\text{Normality}} = {\text{Molarity}} \times {\text{Basicity}}$
Normality of an acid can be calculated by using the given formula.
${\text{Normality}} = {\text{Molarity}} \times {\text{Acidity}}$

Complete step by step answer:
The relationship between volume strength and normality is as follows:
${\text{Normality}} = \dfrac{{{\text{Volume strength of }}{H_2}{O_2}}}{{5.6}}$
Given volume strength of ${H_2}{O_2}$is 5.6
${\text{Normality}} = \dfrac{{{\text{Volume strength of }}{H_2}{O_2}}}{{5.6}} \\\ = \dfrac{{5.6}}{{5.6}} \\\ = 1\,{\text{N}} \\\$
Hence, the normality of ${H_2}{O_2}$is $1\,{\text{N}}$.

Additional Information:
The formula which is used to calculate normality is-${\text{Normality}} = {\text{Number}}\,{\text{of}}\,{\text{gram}}\,{\text{equivalents}} \times {\left[ {{\text{volume}}\,{\text{of}}\,{\text{solution}}\,{\text{in}}\,{\text{litres}}} \right]^{ - 1}}$
Steps involved in the calculation of normality are discussed below.
Step 1: In this step, we need to gather the information about the equivalent weight of the solute or reacting substance.
Step 2: Number of gram equivalent of solute are calculated in this step.
Step 3: The necessary information to be remembered that the volume is to be calculated by litres.
Step 4: Normality is calculated by substituting the values in the given formula.
We know that normality is mostly used in acid-base theory for determining concentration. In a solution it is used to indicate concentration of ${H_3}{O^ + }$ or $O{H^ - }$ ion. In precipitation reactions the number of ions precipitated for a specific reaction is determined by using normality. Number of losing or gaining electrons by an oxidizing or reducing agent is determined by normality.

Note:
Students might get confused between normality and molarity. Normality is the measure of gram equivalent per litre of solution while molarity is the moles per litre of solution.