Question

Volume of N2 at NTP required to form a mono layer on the surface of iron catalyst is 8.15 ml/gram of the adsorbent. What will be the surface area of the adsorbent per gm if each nitrogen molecule occupies 16 × 10–22m2.

• A. 16 × 10–16 cm2
• B. 0.35 m2/g
• C. 0.35 m2/g
• D. 22400 cm2

Answer 1

Answer: (B)

0.35 m2/g

Answer 2

He volume of N2 at STP required to cover the iron surface with monolayer = 8.15 ml gm–1

Area occupied by single molecule = 16 × 10–18 cm2

22400 ml of N2 at STP contains = NA molecule of N2

$\therefore$ 8.15 ..................... = molecule of N2 Area occupied by 2.19 × 1020 molecule of N2 = 2.19 × 1020 × 16 × 10–18 cm2 = 35.06 × 102 cm2

surface area of the iron adsorbed = 0.35 m2 gm–1

In short