Question
Question: Volume of gas at NTP is \( 1.12 \times {10^{ - 7}}c{m^{ - 3}} \) . Calculate the number of molecules...
Volume of gas at NTP is 1.12×10−7cm−3 . Calculate the number of molecules in it.
(A) 3.01×1012
(B) 3.01×1020
(C) 3.01×1024
(D) 3.01×1023
Solution
NTP stands for Normal. Temperature and Pressure. We have given the volume of gas at NTP so to calculate the number of molecules in the gas we will use the basic chemistry of mole concept that 22.4L gas at NTP produces or corresponds to one mole.
Complete step by step answer:
First, we will understand what is given to us in the question and what we need to calculate. So, the question says that Volume of gas at NTP is 1.12×10−7cm−3 which gives us that the volume of gas at Normal, Temperature, and pressure the total molecules or the moles of gas acquires the volume of 1.12×10−7cm−3 . So, now if we calculate the volume of the gas at Normal, Temperature and Pressure which correspond to one mole of the gas we can easily calculate the number of molecules which requires the volume of gas at Normal, Temperature and Pressure which equals to 1.12×10−7cm−3 .
We know that 22.4L gas at NTP produces or corresponds to one mole. In chemistry, we know that one mole of an atom contains 6.02×1023 molecules or particles. The value of 6.02×1023 molecules or particles represents Avogadro's number. Avogadro’s number is represented by NA . So, now we know that 22400cm−3 gas corresponds to 6.02×1023 molecules or particles. So the number of molecules in 1.12×10−7cm−3 of gas will be 224006.02×1023=3.01×1012 molecules.
Therefore, the correct option is (A).
Note:
There is a basic difference between NTP and STP is that STP stands for standard, Temperature, and pressure, and the values at STP are set by IUPAC as T=273.15K and the pressure is 1 bar or 100KPa and NTP is set at T=293.15K and pressure at 101.325KPa .