Solveeit Logo
Login

Question

Chemistry Question on Some basic concepts of chemistry

Volume of a gas at NTP is 1.12×10−7cm31.12\times {{10}^{-7}}c{{m}^{3}} . The number of molecules in it is

A

3.01×10123.01\times {{10}^{12}}

B

3.01×10243.01\times {{10}^{24}}

C

3.01×10233.01\times {{10}^{23}}

D

3.01×10203.01\times {{10}^{20}}

Answer

3.01×10123.01\times {{10}^{12}}

Explanation

Solution

Given, V=1.12×10−7cm3V=1.12 \times 10^{-7} cm ^{3} ∵22400 cm3\because 22400\, cm ^{3} of the gas at STP has molecules =6.02×1023=6.02 \times 10^{23} ∴1.12×10−7cm3\therefore 1.12 \times 10^{-7} cm ^{3} of the gas at STP will have molecules =6.02×102322400×1.12×10−7=\frac{6.02 \times 10^{23}}{22400} \times 1.12 \times 10^{-7} =3.01×1012=3.01 \times 10^{12} molecules